Java quiz. What will happen if you try to compile and run thi

What will happen if you try to compile and run this program?


class Box {
    int b,w;
    void Box(int b, int w) {
         this.b = b;  
         this.w = w;
    }
}

public class MyBox extends Box {
    MyBox() {
         super(10, 15);
         System.out.println(b + "," + w);
     }

     static public void main(String args[]) {
           MyBox box = new MyBox();
     }
}

The program will not compile: the main method incorrectly defined
"10,15" will be displayed
0,0 will be printed
None of these options

Explanation

The program does not compile because there is no matching constructor in the base class to call super(10,15) of the subclass constructor.
void Box (int b, int w) is a method and not a constructor because of specified return type.
In the description of the method main() there is no error: static and public can appear in any order.